PLEASE HELP!

An airplane takes off with an angle of elevation of 26 degrees. If it must clear the 37-m tall tree at the end of its runway, what length of runway does the plane require? Also add a diagram include plane, tree and angle of elevation.

Respuesta :

Answer:

75.9m

Step-by-step explanation:

Please see attachment for diagram

Tan0 = Opp / Adj

Tan 26° = 37 / x

Cross multiply

xTan 26° = 37

Divide both side by Tan 26°

X = 37 / Tan 26°

X = 75.9m

Therefore, the plane needs a run way of 75.9m

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