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A solution contains a mixture of pentane and hexane at room temperature. The solution has a vapor pressure of 246 torr . Pure pentane and hexane have vapor pressures of 425 torr and 151 torr, respectively, at room temperature.
a. What is the mole fraction of hexane? (Assume ideal behavior.)

Respuesta :

jufsanabriasa

Answer:

[tex]X_{hexane} = 0,653[/tex]

Explanation:

The pressure of the solution is:

[tex]P_{solution} = P^0_{hexane}X_{hexane} + P^0_{pentane}X_{pentane}[/tex] (1)

[tex]246torr = 151X_{hexane} + 425X_{pentane}[/tex] (1)

Where X is mole fraction of each compound. Also, you can write:

[tex]1 = X_{hexane} + X_{pentane}[/tex] (2)

Replacing (2) in (1):

[tex]246torr = 151X_{hexane} + 425(1-X_{hexane})[/tex]

-179 = [tex]-274X_{hexane}[/tex]

[tex]X_{hexane} = 0,653[/tex]

I hope it helps!

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