Answer:
The answer to your question is 160 g of Feâ‚‚O₃ Â
Explanation:
Data
mass of Fe = 112 g
mass of CO = in excess
mass of Fe₂O₃ = ?
Balanced chemical reaction
        Fe₂O₃  +  3CO  ⇒  2Fe  +  3CO₂
Process
1.- Calculate the molar mass of Fe₂O₃ and Fe
Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g
atomic mass of Fe = 56
2.- Use proportions to calculate the mass of Fe₂O₃ needed
        160 g of Fe₂O₃ ------------------- 2(56) g of Fe
         x   g of Fe₂O₃ ------------------ 112 g of Fe
         x = (112 x 160) / 2(56)
         x = 17920/112
         x = 160 g of Feâ‚‚O₃     Â