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3. A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is the magnitude of its
acceleration? A = (V-V:)/T
• Show how you set up the problem. (Show your work.)

Respuesta :

olatunbosunadeoke

Answer: 0.83m/s^2

Explanation:

Acceleration is the rate of change in speed in one second. Its standard unit is metres per second square (m/s^2)

Recall that at rest, the speed of train (V:) = 0

Final speed of train (V) = 25 m/s

Time taken (T) = 30.0 seconds

Magnitude of Acceleration = (Final speed V - resting speed V:) / Time taken

Acceleration = (25 - 0) / 30

= 25m/s / 30s

= 0.83 m/s^2

Thus, the magnitude of acceleration with the train moves with is 0.83 metres per seconds square

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