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What is the mass of a piece of iron if it absorbs 5575 joules of heat and its specific heat capacity is 0.95 J/g°C? The initial temperature of the iron is 20.0°C and is raised to 30°C.



Only include numbers and the decimal point in your answer. If necessary, round to the hundredths (two spots to the right of the decimal point) place. For example "34.22."

Respuesta :

Answer:

The mass of iron piece = 586.84

Explanation:

Given,

Heat absorbed by iron piece(Q) = 5575 Joules.

specific heat capacity(Cp) = 0.95 J/g°C.

initial temperature(T₁) = 20.0°C

Final temperature(T₂) = 30.0°C

Mass of iron piece(m) = ?

The mass of iron piece can be calculated by using the formula ,

Q = (mass) (ΔT) (Cp)

Here, ΔT = T₂ - T₁ = 30°C - 20°C = 10°C

Substituting values we get,

5575 = (m)(10)(0.95)

Solving, we get,

m = 586.84 grams.

Therefore, mass of iron piece = 586.84 grams.

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