shewillbeloved46
shewillbeloved46 shewillbeloved46
  • 18-03-2020
  • Mathematics
contestada

Somebody please help meeeee

Somebody please help meeeee class=

Respuesta :

Wallind11
Wallind11 Wallind11
  • 18-03-2020

Step-by-step explanation:

[tex] \frac{2 + 3i}{4 - 5i} [/tex]

[tex] \frac{(2 + 3i)(4 + 5i)}{(4 - 5i)(4 + 5i)} [/tex]

[tex] \frac{8 + 10i + 12i + 15 {i}^{2} }{16 - 25 {i}^{2} } [/tex]

[tex] \frac{8 + 22i + 15( -1 )}{16 - 25 ( - 1)} [/tex]

[tex] \frac{8 - 15 + 22i}{16 + 25} [/tex]

[tex] \frac{ - 7 + 22i}{41} [/tex]

So, a= -7

b= 22

c= 41

Answer Link

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