Explanation:
u=20m/s
v=0m/s
g= 9.8m/s^2
h=?
v^2 = u^2 -2gh
0^2 = 20^2 -2 ×9.8×h
19.6h=400
19.6h/19.6 = 400/19.6
h=20.41m
solving for time taken for the ball to reach the ground again T =the time to reach maximum height + time the Ball takes to fall to the ground .
The time t to reach maximum height = The time t to fall to the ground
T = t+t
T=2t
u=20m/s
v=0m/s
g= 9.8m/s^2
t=?
v= u-gt
0=20-9.8t
9.8t=20
9.8t/9.8 = 20/9.8
t= 2.04seconds
T=2t
T=2(2.04)
T=4.08 seconds is the time the ball takes to reach the ground again.
