Answer:
0.098 moles of HNO₃ are present if 4.90×[tex]10^{-2}[/tex] mol of Ba(OH)₂ was needed to neutralize the acid solution
Explanation:
1 mole of Ba(OH)₂ contains 2 moles of OH- ions.
Hence, 0.049 moles of Ba(OH)2 contains x moles of OH- ions.
cross multiplying, we have
1 mole * x mole = 2 moles * 0.049 mole
x mole = 2 * 0.049 / 1
x mole = 0.098 moles of OH- ions.
1 mole of OH- can neutralize 1 mole of H+
Therefore, 0.098 moles of HNO₃ are present if 0.049 moles of Ba(OH)₂ was needed to neutralize the acid solution.
