Answer:
31.005 KJ
Explanation:
We are given that
Mass of hammerhead=25 kg
Initial velocity,u=0
Final velocity,v=50 m/s
h=-1 m
h'=0
We have to find the change in total energy of the hammerhead.
Change in total energy=[tex]E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')[/tex]
Using the formula
Change in internal energy of hammerhead=[tex]m(u_2-u_1)=0[/tex]
Change in total energy=[tex]\frac{1}{2}(25)(50)^2+25\times 9.8(-1)[/tex]
Where [tex]g=9.8m/s^2[/tex]
Change in total energy=[tex]31005 J=\frac{31005}{1000}=31.005 KJ[/tex]
1 KJ=1000 J
