rodriguezjoseph8707 rodriguezjoseph8707
  • 20-03-2020
  • Physics
contestada

What is the apparent weight of this same object at Neptune's equator? (Note that Neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.)

Respuesta :

Stinflame
Stinflame Stinflame
  • 22-03-2020

Answer:

Explanation:

Acceleration of gravity on the surface of

Neptune is given

g' = G M/R^2,

where M is the planet's mass.

M g' will be the apparent weight registed at the poles.

G is the universal constant of gravity

The "apparent weight" at the equator will be

reduced from M g' by the centripetal force M

R w^2, where w is the rotational angular

velocity in radians/s), which you can deduce

from the 16 hour length of a day.

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