Respuesta :
Answer with explanation:
It is given that
[tex]4^2=16\\\\ \text{taking log on both sides}\\\\ 2 \log 4=\log 16\\\\ \frac{\log 16}{\log 4}=2\\\\\log_{4}16=2[/tex]
Which is in logarithmic form of base.
[tex]\log_{a}b}=\frac{\log b}{\log a}[/tex]