The answer for the following problem is mentioned below.
Explanation:
Given:
mass of iron (m) = 15.75 grams
heat (q) = 1097 J
initial temperature ([tex]t_{1}[/tex]) = 25°C
final temperature ([tex]t_{2}[/tex]) = 177°C
To find:
specific heat (c)
We know;
c = q ÷ mΔT
where;
c represents the specific heat
q represents the heat
m represents the mass
t represents the temperature
c = [tex]\frac{1097}{15.75 * (177-25)}[/tex]
c = 0.45 J/kg°C
Therefore the specific heat capacity of iron is 0.45 J/kg°C.
