Respuesta :

Wallind11

Answer:

Let y = f(x)

[tex] = > y = \frac{19}{ {x}^{3} } [/tex]

[tex] = > {x}^{3} = \frac{19}{y} [/tex]

[tex] = > x = \sqrt[ 3]{ \frac{19}{y} } [/tex]

[tex] {f}^{ - 1} (x) = \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} } [/tex]

option A