resssssssmicanett resssssssmicanett

17-08-2016
Chemistry

contestada

a solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12

Respuesta :

Willchemistry Willchemistry

17-08-2016

pOH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

pOH = 12

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wegnerkolmp2741o wegnerkolmp2741o

09-05-2020

Answer:

12

Explanation:

p(oh) = - log ( concentration of the oh) = -log (1* 10^-12) = - (-12) = 12

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