nikkiekermel nikkiekermel

18-08-2016
Chemistry

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calculate the [oh−] in a solution with a ph of 12.52.

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Willchemistry Willchemistry

19-08-2016

pH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M

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