nickkkkkkk nickkkkkkk
  • 16-05-2020
  • Mathematics
contestada

Determine the center and radius of the following circle equation:
x² + y² - 10x + 20y + 89 = 0

Respuesta :

PollyP52 PollyP52
  • 16-05-2020

Answer:

The center is ( -5, -10) and the radius = 6.

Step-by-step explanation:

Convert the equation to standard form by completing the square;

x^2 + y^2 - 10x + 20y + 89 = 0

x^2 + y^2 - 10x + 20y  = -89

x^2 - 10x + y^2  + 20y  = -89   Completing the square:

(x + 5)^2 - 25 + (y + 10)^2 - 100 = -89

(x + 5)^2 + (y + 10)^2 = -89  + 125

(x + 5)^2 + (y + 10)^2 =  36

Comparing this to the standard form:

( x - h)^2 + (y - k)^2 = r^2

- we see that the center is ( -5, -10) and the radius = 6.

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