marcellabella9 marcellabella9

18-05-2020
Chemistry

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How many moles of oxygen are required to react completely with 16.5 mol Al?

Respuesta :

SvetkaChem SvetkaChem

18-05-2020

Answer:

12.4 mol O2

Explanation:

4Al + 3O2 -----> 2Al2O3

from reaction 4 mol 3 mol

given 16.5 mol x mol

x = 16.5*3/4 =12.4 mol O2

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