blob23 blob23
  • 20-05-2020
  • Mathematics
contestada

Solve 2sin^2x=sinx, if 0

Respuesta :

batmandance18
batmandance18 batmandance18
  • 21-05-2020
Explanation:
sin
x
(
2
sin
x
+
1
)
=
0

Use trig table and unit circle -->
a. sin x = 0 => x = 0, and
x
=
π
and
x
=
2
π
b. 2sin x + 1 = 0 =>
sin
x
=
−
1
2
=>
x
=
7
π
6
and
x
=
11
π
6
.
Finally, within interval
[
0
,
2
π
]
,
there are 5 answers:
0
,
π
,
2
π
,
7
π
6
and
11
π
6
Answer Link
vh88639 vh88639
  • 11-03-2022

Answer: D. 0, pi/6, pi, 5pi/6, and 2pi

Step-by-step explanation:

Refer to screenshot of Desmos graph below

Question: What are all the exact solutions of [tex]2sin^2x-sinx=0[/tex] for [tex]0\leq x\leq 2\pi[/tex]?

Ver imagen vh88639
Ver imagen vh88639
Answer Link

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