Respuesta :

masbrosur

Answer:

[tex] \frac{9c + 160}{5} [/tex]

Step-by-step explanation:

C = 5(F - 32)/9

so we do a little algebra here

9C = 5F - 160

we move both side

5F - 160 = 9C

5F = 9C + 160

so in the end

F =

[tex] \frac{9c + 160}{5} [/tex]

a = 9

b = 160

c = 5

09pqr4sT

Answer:

[tex]F=\frac{9C+160}{5}[/tex]

Step-by-step explanation:

[tex]C=\frac{5(F-32)}{9}[/tex]

Multiply both sides with 9.

[tex]9C=5(F-32)[/tex]

Use distributive property.

[tex]9C=5F-160[/tex]

Add 160 to both sides.

[tex]9C+160=5F[/tex]

Divide 5 to both sides.

[tex]\frac{9C+160}{5}=F[/tex]

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