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  • 17-06-2020
  • Chemistry
contestada

what is the new temperature when 10 L at 5 K is compressed to 4.00 L
a) 20 K
b) 25 K
c) 2 K
d) 0.5 K

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  • 17-06-2020

Answer: C

Explanation:

For this problem, we would use Charles's Law. We fill in what we are given and solve.

Charles's Law: [tex]\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }[/tex]

[tex]\frac{10 L}{5K} =\frac{4.00L}{T_{2} }[/tex]

[tex]10T_{2}= 20[/tex]

[tex]T_{2}=2K[/tex]

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