kevini63 kevini63

18-06-2020
Mathematics

contestada

[tex] \frac{a(3 + a)}{3} \leqslant \frac{z(a - 1) {}^{2} }{15} - \frac{(a - 1)(4 - a)}{5} + \frac{1}{5} [/tex]
can anyone help me?

Respuesta :

lindsaycpayton lindsaycpayton

18-06-2020

a= 15+z+ square root 17(z+15)/ z-2
z=2a^2/(a-1)^2 + 30a/(a-1)^2 - 15/(a-1)^2

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