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  • 18-06-2020
  • Mathematics
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Question #13, how to solve for the value of x in the triangle? Whoever answers right will receive brainliest.

Question 13 how to solve for the value of x in the triangle Whoever answers right will receive brainliest class=

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senuthibihansa25 senuthibihansa25
  • 18-06-2020

Answer:x=8 or x=-4

Step-by-step explanation:

x²+(x+7)² = (x+9)²

x²+(x+7)(x+7) = (x+9)(x+9)

x²+x²+7x+7x+49 = x²+9x+9x+81

2x²+14x+14x+49 = x²+18x+81

2x²-x²+14x-18x = 81-49

x²-4x = 32

(x²-4x)-32 = 0

(x+2x)(x-2x)-32 = 0

x²+2x²-2x²-4x-32 = 0

x²-4x-32 = 0

(x-8)(x+4) = 0

(x-8) = 0 or (x+4) =0

x = 8 or x = -4

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