Answer:
(3y - 1)(2y - 5)
Step-by-step explanation:
Given
6y² - 17y + 5
Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.
product = 6 × 5 = 30 and sum = - 17
The factors are - 2 and - 15
Use these factors to split the y- term
6y² - 2y - 15y + 5 ( factor first/second and third/fourth terms )
= 2y(3y - 1) - 5(3y - 1) ← factor out (3y - 1) from each term
= (3y - 1)(2y - 5) ← in factored form
