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18-06-2020
Mathematics

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consider the quadratic equation y^2-y=6. what is the error with the solution below?

Respuesta :

26-06-2020

Answer:

y=-2 or y=3

Step-by-step explanation:

Y^2-y-6=0

y^2-3y+2y-6=0

y(y-3)+2(y-3)=0

(y+2)(y-3)=0

y=-2 or y=3

hope it helps

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