sammygirl73
sammygirl73
19-06-2020
Mathematics
contestada
Solve: 4x^-2 – 3x^-1– 1 = 0
Respuesta :
mhanifa
mhanifa
03-09-2020
Answer:
1, -4
Step-by-step explanation:
4x^-2 – 3x^-1– 1 = 0
Let x^-1 = 1/x = y
4y^2 - 3y - 1 = 0
4y^2 - 4y + y - 1 = 0
(y - 1) (4y + 1) = 0
1. Root 1
y - 1 = 0
y = 1
1/x= 1
x = 1
2. Root 2
4y + 1 = 0
4y = -1
y = -1/4
1/x = - 1/4
x = -4
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