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The isosceles triangle and the square shown here have the same area in square units. What is the height of the triangle, $h$, in terms of the side length of the square, $s$?

The isosceles triangle and the square shown here have the same area in square units What is the height of the triangle h in terms of the side length of the squa class=

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Answer:

h = 2s

Step-by-step explanation:

Area of square is equal to the area of triangle in this question.

the area of the square is s²

the area of the triangle is [tex]\frac{1}{2}[/tex] *h*s

s²=  [tex]\frac{1}{2}[/tex] *h*s

s = [tex]\frac{1}{2}[/tex] *h

2s = h

hope that helps

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