Answer:
The acceleration of the crate is 7.5 m/s²
Explanation:
Given;
force exerted on the crate, F₁ = 500 N
mass of the crate, m = 40 kg
frictional force between the floor and the crate, F₂ = 200 N
The net horizontal force is given by;
∑Fₓ = F₁ - F₂
∑Fₓ = 500 N - 200 N
∑Fₓ = 300 N
Apply Newton's second law of motion to determine the acceleration of the crate;
∑Fₓ = ma
a = ∑Fₓ / m
a = 300 N / 40 kg
a = 7.5 m/s²
Therefore, the acceleration of the crate is 7.5 m/s²
