Answer:
[tex]a=1.67\frac{m}{s^2}[/tex]
Explanation:
Hello,
In this case, since the acceleration is defined as the velocity change from final to initial divided by the time:
[tex]a=\frac{v_f-v_0}{t}[/tex]
We obtain it with the proper units:
[tex]v_f=66\frac{km}{h} *\frac{1h}{3600s}*\frac{1000g}{1km}=18.3\frac{m}{s}[/tex]
[tex]a=\frac{18.3\frac{m}{s} -0\frac{m}{s} }{11s} \\\\a=1.67\frac{m}{s^2}[/tex]
Best regards.
