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  • 18-09-2020
  • Chemistry
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Calculate the mass of NaOH required to make 300 CM3 of 0.2M solution​

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Аноним Аноним
  • 18-09-2020

Answer:

Mass of NaOH = 2.4 grams

Explanation:

[tex]M\:=\:\frac{n}{v}[/tex]

where,

[tex]n=moles\:of\:solute[/tex]

[tex]v=liters\:of\:solution[/tex]

Remember:    [tex]\quad 1000\:cm^3=1\:L[/tex]

[tex]\Rightarrow \quad 300\:cm^3=0.3\:L[/tex]

[tex]n=\frac{m}{40\:g/mol}[/tex]

Putting the values, we have:

[tex]0.2=\frac{m}{40\:g/mol}\times \frac{1}{0.3}[/tex]

[tex]\Rightarrow m=2.4\:g[/tex]

Best Regards!

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