Explanation:
Given that,
The magnitude of vector A = 217 units to north
The magnitude of vector B = 156 units to west
Let R is the resultant. So,
[tex]R=\sqrt{217^2+156^2} \\\\R=267.25\ \text{units}[/tex]
Let [tex]\theta[/tex] is the direction of the resultant vector. So,
[tex]\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{217}{156}\\\\\theta=\tan^{-1}\left(\dfrac{217}{156}\right)\\\\\theta=54.28^{\circ}[/tex]
Hence, this is the required solution.
