cisabelr cisabelr

18-09-2016
Mathematics

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How to graph the following: y=-3(x-2)^2+4

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apologiabiology apologiabiology

18-09-2016

ok sowe have
y=a(x-h)^2+k
h,k is vertex

y=-3(x-2)^2+4
vertex is (2,4)

since a is negative, graph opens down

so at point (2,4)< draw a parabola opening down, going through point (0,4)

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