Answer:
There is no real solution
Step-by-step explanation:
[tex]6x^2-28x = - 16\\\\6x^2-28x + 16=0\\\\3x^2-7x+8=0\\\\9x^2-21x+24=0\\\\(3x)^2-2\cdot3x\cdot\frac72+(\frac72)^2-(\frac72)^2+24=0\\\\(3x-\frac72)^2-\frac{49}4+24=0\\\\(3x-\frac72)^2-12\frac{1}4+24=0\\\\(3x-\frac72)^2+12\frac{3}4=0\\\\(3x-\frac72)^2=-12\frac{3}4[/tex]
