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19-10-2020
Mathematics

contestada

if
[tex]f(x) = \frac{1}{9} x - 2[/tex]
what is
[tex] {f}^{ - 1} (x)[/tex]

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cromulent cromulent

19-10-2020

Let [tex]y = f^{-1}(x)[/tex] and [tex]f(y) = x[/tex]

[tex]\frac{1}{9}y - 2 = x\\\frac{1}{9}y = x + 2\\y = 9x + 18\\f^{-1}(x) = 9x + 18[/tex]

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