Complete Question
A coal train in Montana starts from rest and accelerates at 2.5m/s^2 for 15 Find the trains maximum velocity
Answer:
The maximum velocity is [tex]v = 37.5 \ m/s [/tex]
Explanation:
From the question we are told that
The acceleration is [tex]a =2.5\ m/s^2[/tex]
The time for the acceleration is [tex]t = 15 \ s[/tex]
Generally from the kinematics equation
[tex]v = u + at[/tex]
here u is the initial velocity and the value is 0 m/s given that it started rom rest
[tex]v = 0 + 2.5 * 15[/tex]
[tex]v = 37.5 \ m/s [/tex]
