Respuesta :

chloeoak07

Answer:

1st integer=x

2nd integer=x+1

3rd integer=x+2

4th integer=x+3

 

2(x +(x+2))= 3(x+1) +11

 

solve

 

2 (2x +2) = 3x + 3 + 11

 

4x + 4     = 3x + 14

 

-3x-4       =-3x -4

 

 

           x=10

 

1st integer=10

2nd integer=11

3rd integer=12

4th integer=13

Step-by-step explanation:

hopefully this helped

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