Respuesta :

kdai253

Answer:

You can show that the function is one-to one by setting f(x)=f(y) and determining if f(x)=f(y)

Step-by-step explanation:

So, you could

(y-2)^3+8=(x-2)^3+8 and determine if x=y

(y-2)^3=(x-2)^3

=cube root both sides

y-2=x-2

y=x

func is 1 to 1

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