Answer: i) [tex]p=\dfrac{d-3}{2}[/tex]
ii) He has to attend 5 practices to run 13 miles.
Step-by-step explanation:
Given: The distance (d) in miles that Cecil runs depends on the number of track practices (p) he attends.
[tex]d=2p+3[/tex]
i) To solve for p . first subtract 3 from both sides , we get
[tex]d-3=2p[/tex]
Divide both sides by 2
[tex]\dfrac{d-3}{2}=p[/tex]
So. [tex]p=\dfrac{d-3}{2}[/tex]
ii) Put d= 13 , we get
[tex]p=\dfrac{13-3}{2}=\dfrac{10}{2}=5[/tex]
i.e. he has to attend 5 practices to run 13 miles.
