Answer:
Step-by-step explanation:
It may be easier to find the sum, then "rationalize" the denominator.
[tex]\dfrac{2i}{2+i}-\dfrac{3i}{3+i}=\dfrac{2i(3+i)-3i(2+i)}{(2+i)(3+i)}=\dfrac{6i+2i^2-6i-3i^2}{6+5i+i^2}\\\\=\dfrac{1}{5+5i}=\dfrac{5-5i}{(5+5i)(5-5i)}=\dfrac{5-5i}{25+25}=\dfrac{5-5i}{50}\\\\=\boxed{0.1-0.1i}[/tex]
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Of course, it doesn't hurt to have a suitable calculator.
