Answer:
y = 1
Step-by-step explanation:
Given the equation: [tex]36^{y-1}\times6^{2y-2}=1[/tex]
This equation can be turned into:
[tex]6^{y-1}\times6^{y-1}\times6^{2y-2}=1[/tex]
Simplified to:
[tex]6^{4y-4}=1[/tex] (using the law of indices)
Since all numbers to the power of 0 equal 1:
∴ [tex]4y-4=0[/tex]
Which concludes that y = 1.
