contestada

n LC circuit has an oscillation frequency of 105 Hz. If C = 0.1 F , then L must be about:

Respuesta :

Answer:

L = 22.97 H

Explanation:

Given that,

Capacitance, [tex]C=0.1\ \mu F=0.1\times 10^{-6}\ F[/tex]

Oscillation frequency, f = 0.5 Hz

The frequency of an AC circuit is given by :

[tex]f=\dfrac{1}{2\pi \sqrt{LC} }[/tex]

Where

L is impedance

[tex]f^2=\dfrac{1}{4\pi ^2LC}\\\\L=\dfrac{1}{4\pi ^2 f^2 C}\\\\\text{Putting all the values}\\\\L=\dfrac{1}{4\pi^2 \times (105)^2\times 0.1\times 10^{-6}}\\\\L=22.97\ H[/tex]

So, the impedance of LC circuit 22.97 H.