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A chemical process converts molten iron (III) oxide into molten iron and carbon dioxide by using a reducing agent of carbon monoxide. The process allows 10.08 kg of iron to be produced from every 16.00 kg of iron (III) oxide in an excess of carbon monoxide. Calculate the percentage yield of iron produced in this process.

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Answer:

percentage yield = 63%

Explanation:

The yield efficiency or percentage yield measure the amount of products that are formed from a given amount of reactant. For a percentage yield of 100, all the reactants are completely converted to product. Mathematically, the percentage yield is given by:

[tex]percentage\ yield = \frac{Actual\ yield}{expected\ yield} \times 100\\Actual\ yield = 10.08kg\\Expected\ yield= 16.00kg\\\\\therefore percentage\ yield = \frac{10.08}{16.00} \times 100 = 63 \%[/tex]

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