Answer:
The correct option is (a).
Explanation:
Given that,
The energy of photon, E = 2.52 eV
We need to find the wavelength of the photon in nm. The formula for the energy of a photon is given by :
[tex]E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{2.52\times 1.6\times 10^{-19}}\\\\=4.93\times 10^{-7}\ m\\\\=493\ nm[/tex]
The nearest option is a) i.e. 492.34127 nm.
