Respuesta :

maacastrobr

Answer:

1.828 g

Explanation:

The half-reaction is:

  • Li⁺ + 1e⁻ → Li(s)

First we calculate the coulombs:

  • Coulombs = Amperes * seconds
  • 23.93 hr * 60 = 1435.8 s
  • Coulombs = 17.7 A * 1435.8 s = 25413.66 C

Then we calculate the number of lithium moles, using Faraday's constant:

  • 25413.66 C * [tex]\frac{1mol(e^-)}{96485C} *\frac{1molLi}{1mol(e^-)}[/tex] = 0.2634 mol Li

Finally we convert moles to grams:

  • 0.2634 mol Li * 6.941 g/mol = 1.828 g

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