Answer:
The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N
Explanation:
Given;
speed of proton, v = 850 m/s
magnitude of magnetic field, B = 0.7 T
Charge of proton, q = 1.602 x 10⁻¹⁹ C
The magnitude of the magnetic force on the proton;
F = qvB
F = ( 1.602 x 10⁻¹⁹)(850)(0.7)
F = 9.532 x 10⁻¹⁷ N.
Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N
