jjoemama20005 jjoemama20005

20-11-2020
Mathematics

contestada

can someone help me please and thank you

can someone help me please and thank you class=

Respuesta :

ackahedem582 ackahedem582

23-11-2020

Answer:

2y.

Step-by-step explanation:

18x^2y^2/9x^2y

18/9.x^(2 - 2)y^(2 - 1)

2x^0y^1

2y.

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