find the equation of the tangent line to 9x^2+16y^2=52 through (2,-1). A. -9x+8y-26=0. B. 9x-8y-26=0. C. 9x-8y-106=0. D. 8x+9y-17=0. E. 9x+16y-2=0 . the slope is 9/8 idk where to go from there...
plug in for 0, to find the slope which will get you - 9/16. and you know that the tangent of the line formula is y - y1 = m (x -x1), and the problem gave you the points for y1 and x1.
so the line tangent is y = - 9/16 (x - 2) - 1
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