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19-10-2016
Mathematics

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(-1,5) (3,13) what is the equation

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sakarpathak111 sakarpathak111

19-10-2016

(-1,5) = (x1,y1)
(3,13) = (x2,y2)
slope(m) = (y2-y1)/(x2-x1)
= 2
by using slope point form
y-y1 = m (x-x1)
y-5 = 2(x+1)
2x-y+7=0

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