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You have been given three plants: Two have solid black flowers, and one has grey flowers. You cross each black-flowered plant to the grey plant with the following results:
Parents: black #1 X grey F1: 87 solid black, 83 spotted black
Parents: black #2 X grey F1: all black
To try and make sense of these results, you intercross the solid black-flowered F1 plants from cross #2 with the following results in the F2:
132 black
35 spotted black
11 grey
What are the genotypes of the parents, F1 and F2 generations?

Respuesta :

Histrionicus

Answer:

The correct answer would be -

F1: #1 black flower plant = Aabb and aabb and #2 = AABB and aabb

F2 = AaBb and AaBb

Explanation:

In this cross, it is the case of the dominant epistasis type of inheritance pattern as Gene A masks the expression of gene B but expresses itself only in presence of b or B.

The ratio of the dihybrid cross change in such inheritance from  9: 3: 3: 1 ratio changes to 12: 3: 1.

Check for the images for cross:

Ver imagen Histrionicus
Ver imagen Histrionicus