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Laboratory work often involves making dilutions of standard solutions. Dilution problems are not hard, but they can sure get you confused if you aren't careful. The following relation can often save you from pulling all of your hair out:

C1V1= C2V2
Where,

V1 = initial volume
C1 = initial concentration
V2 final volume
C2= final concentration

A 0.6M solution of NaOH is diluted from 100 ml to 1liter. What is the new NAOH concentration?

Respuesta :

samueladesida43

Answer:

0.06M

Explanation:

Using the formula as outlined in this question,

C1V1= C2V2

Where;

V1 = initial volume (Litres)

C1 = initial concentration (M)

V2 = final volume (Litres)

C2 = final concentration (M)

According to the information provided on NaOH in this question, V1 = 100mL = 100/1000 = 0.1 L, V2 = 1L, C1 = 0.6M, C2 = ?

C1V1= C2V2

0.6 × 0.1 = C2 × 1

0.06 = C2

C2 = 0.06M

The new concentration of NaOH is 0.06M.

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