Answer:
Area is increasing
Step-by-step explanation:
Let x be the length of rectangle and y be the width of rectangle
We are given that
x=3 in
dx/dt=1 in/min
y=2 in
dy/dt=-0.5/min
We know that
Area of rectangle,[tex]A=xy[/tex]
Differentiate w.r.t t
[tex]\frac{dA}{dt}=y\frac{dx}{dt}+x\frac{dy}{dt}[/tex]
Substitute the values
[tex]\frac{dA}{dt}=2(1)+3(-0.5)=2-1.5=0.5 in^2/min[/tex]
Hence, the area of rectangle is increasing.
